Intrinsic carrier concentration of a silicon sample at 300 K is 1.5x 10¹ m3. After doping, the number of majority carriers is 2.25 x 1020 m³. The minority carrier density is
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Explanation:
Given Intrinsic carrier concentration of a silicon sample at 300 K is 1.5 x 10^10 m3. After doping, the number of majority carriers is 2.25 x 1020 m³. The minority carrier density is
- So given is n type semi conductor.
- Doping concentration or donor concentration
- Nd = 2.25 x 10^20 m^3
- So Nd is approximately equal to Nn (electron concentration under equilibrium)
- Now to find minority carriers using mass action law
- under thermal equilibrium the product of total positive charge and total negative charge is always constant and is equal to square of intrinsic carrier concentration.
- N.P = Ni^2
- for n type Nn Pn = Ni^2
- Np Pn = Ni^2
- So Pn = Ni^2 / Np
- Pn = (1.5 x 10^10)^2 / 2.25 x 10^20
- = 1.0 / cm^3
Reference link will be
https://brainly.in/question/8537702
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