Physics, asked by boiikanaik, 1 month ago

Intrinsic carrier concentration of a silicon sample at 300 K is 1.5x 10¹ m3. After doping, the number of majority carriers is 2.25 x 1020 m³. The minority carrier density is​

Answers

Answered by charnpreetsingh3247
0

Answer:

srry ... I don't know...

Answered by knjroopa
0

Explanation:

Given Intrinsic carrier concentration of a silicon sample at 300 K is 1.5 x 10^10 m3. After doping, the number of majority carriers is 2.25 x 1020 m³. The minority carrier density is

  • So given is n type semi conductor.
  • Doping concentration or donor concentration
  •                               Nd = 2.25 x 10^20 m^3  
  •                             So Nd is approximately equal to Nn (electron concentration under equilibrium)
  • Now to find minority carriers using mass action law  
  • under thermal equilibrium the product of total positive charge and total negative charge is always constant and is equal to square of intrinsic carrier concentration.
  •                                               N.P = Ni^2  
  •                   for n type Nn Pn = Ni^2
  •                                     Np Pn = Ni^2
  •                                     So Pn = Ni^2 / Np
  •                                          Pn = (1.5 x 10^10)^2 / 2.25 x 10^20
  •                                                = 1.0 / cm^3

Reference link will be

https://brainly.in/question/8537702

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