Question

ints P(2, -3) and Q(10,y) is 10
12. Find the values of y for which the distance between the points P(2, -3) and
2. Find the valuese
units.​

Answer 1

use distance formula and apply values

Answer 2

Answer:

y=3unit or y=-9unit

Step-by-step explanation:

by distance formula

PQ=√(x2-x1)^2+(y2-y1)^2

putting the value

(10)^2=(10-2)^2+[y-(-3)]^2

100=64+y^2+6y+9

y^2+6y-27=0

(y^2+9y)-(3y-27)=0

take common

y(y+9)-3(y+9)=0

y-3=0

y=3

or

y+9=0

y=-9