Math, asked by subarna41, 5 hours ago

invalid answer will be reported...plz answer fast with a propet explanation​

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Answered by mohit762161
0

Step-by-step explanation:

 \frac{34}{(3x + 4y)}  +  \frac{15}{(3x - 2y)}  = 5 \\  \frac{34(3x - 2y) + 15(3x + 4y)}{(3x + 4y)(3x - 2y)}  = 5 \\  \frac{102x - 68y + 45x + 60y}{3x(3x - 2y) + 4y(3x - 2y)}   = 5 \\  \frac{57x -  8y}{9 {x}^{2} - 6xy + 12xy - 8 {y}^{2}  }  = 5 \\   \frac{(57x - 8y)}{(9 {x}^{2}  - 8 {y}^{2}  + 6xy)} = 5   \\  57x - 8y = 5{(9 {x}^{2}  - 8 {y}^{2}  + 6xy)} \\ 57x - 8y = 45 {x}^{2}  - 40 {y}^{2}  + 30xy \\  - 45 {x}^{2}   + 40 {y}^{2}   -  30xy + 57x - 8y = 0

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