Question

invalid answer will be reported...plz answer fast with a propet explanation​

Answer 1

Step-by-step explanation:

$\frac{34}{(3x + 4y)} + \frac{15}{(3x - 2y)} = 5 \\ \frac{34(3x - 2y) + 15(3x + 4y)}{(3x + 4y)(3x - 2y)} = 5 \\ \frac{102x - 68y + 45x + 60y}{3x(3x - 2y) + 4y(3x - 2y)} = 5 \\ \frac{57x - 8y}{9 {x}^{2} - 6xy + 12xy - 8 {y}^{2} } = 5 \\ \frac{(57x - 8y)}{(9 {x}^{2} - 8 {y}^{2} + 6xy)} = 5 \\ 57x - 8y = 5{(9 {x}^{2} - 8 {y}^{2} + 6xy)} \\ 57x - 8y = 45 {x}^{2} - 40 {y}^{2} + 30xy \\ - 45 {x}^{2} + 40 {y}^{2} - 30xy + 57x - 8y = 0$