inverse laplace transforms of
f(s)= S-2÷S^2-4S+13
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Step-by-step explanation:
Method 1: Partial fraction decomposition and table memorization.
s+2s2−4s+13=s+2(s−2)2+9=s−2(s−2)2+32+4(s−2)2+32=s−2(s−2)2+32+433(s−2)2+32
Simply knowing that
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