inverse method. 2x-y+8Z=13 3x+44+5Z=18 ,50-24+7Z=20
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Given equations are 3x + 4y + 5z = 18, 2x - y + 8z = 13,5x - 2y + 7z = 20
3
4
5
-1 8=3(-7+16) - 4(14-40) + 5-2 7
2
5(-4+5)
= 3(9)-4(-26) +5(1)=27+ 104 +5=136
18 4 5 D₁ = 13 -1 8 20 -2 7 =18(-7+16) - 4(91 - =
160) +5(-26+20)
= 18(9) - 4(-69) + 5(-6) 162 +276-30= = 408
3 18 5
D₂ 2 13 8 -3(91-160) - 18(14
5 20 7
40) + 5(40-65)
= 3(-69) - 18(-26)+5(-25)=-207+ 468 125 136 =
3 2 -1 18 13 = 3(-20+26) - 4(40 5 -2 20 D3
65) + 18(-4+5)
= 3(6) -4(-25) + 18(1) = 18+ 100+ 18 = 136
Now, x= D₁ D 408 136 3
D2
136
y = D D3 D 136 136 136 Z= Hence, the solution for the system
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