Math, asked by prity562, 10 months ago

inverse of a positive operator with spectral radius less than 1

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Answered by Sahrin
0

Answer:

Let A be a positive matrix, assume that its spectral radius ρ(A) = 1 (otherwise consider A/ρ(A)). Hence, there exists an eigenvalue λ on the unit circle, and all the other eigenvalues are less or equal 1 in absolute value. ... Moreover, if Ax = λx then Amx = λmx thus λm − ε is an eigenvalue of T.

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