Question

inverse proportions. Two different sums if u can do it on a rough copy. ​

Answer 1

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Answer 2

Answer:

change the variation to an equation by multiplying by a constant.

z = k /(cube root x)

now, putting value

5 = k /( cube root 64 )

=> 5 = k/4

=> k=5×4

=> k= 20

now, replace k with 20 to obtain the equation

z = 20/(cube root x)

Now, you can calculate z for any given x

z = 20/ ( cube root 216 )

z = 20 / 6

z = 10 / 3

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