Math, asked by rrk13, 5 hours ago

inverse trigonometric functions ​

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Answered by xxitzbabygirlxx20
9

Answer:

\huge\mathfrak\orange {Answer}

 \frac{x - 1}{x  + 1}  +  \frac{2x - 1}{2x + 1}  =  \frac{23}{36}

[   1 -  \frac{(x - 1)(2x - 1)}{(x + 1)(2x + 1)}    ]

24 {x}^{2}  - 23x - 12 = 0 = (3x - 4)(8x + 3)=0\huge\mathfrak\blue  { Answer  =  (D) none of these }

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