Question

Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarization of light in the polarimeter. If r, rt and r0 are the rotations at t = , t = t and t = 0 then, first order reaction can be written as

Answer 1

Inversion of a sugar follows first order rate equation: k = (1/t)(ln) (ro-r∞/rt-r∞)

Explanation:

For a first order reaction A→P, the expression for the rate constant is

k = (1/t)(ln) (a/a-x)

Here A is the reactant, P is the product, a is the initial concentration of A and a-x is the concentration of A at time t.

The inversion of a sugar follows first order rate equation which is given below:

k = (1/t)(ln) (ro-r∞/rt-r∞)

Here a = ro-r∞ and a-x = rt-r∞