Math, asked by simon57, 1 month ago

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8. Simplify:
cosec(90°–0).coso+sinocoto
sin(900-0).seco-coso.tano

Answers

Answered by ketakisshigwan1983
0

Answer:

As we know that,

sin(90  

o

−θ)=cosθ, cos(90  

o

−θ)=sinθ,

cosec(90  

o

−θ)=secθ, cot(90  

o

−θ)=tanθ,

sec(90  

o

−θ)=cosecθ, tan(90  

o

−θ)=cotθ

∴  

cosec(90−θ)sin(90−θ)cot(90−θ)

cos(90−θ)sec(90−θ)tanθ +  cotθ

tan(90−θ)

​∴ sin(90−θ) 1 ×sin(90−θ)×tanθ

sinθ×  cos(90−θ) 1  ×tanθ  +  cotθ

cotθ =  cosθ 1  ×cosθ

sinθ×  sinθ

1 +1  

=1+

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