Math, asked by renukagupta29pa04py, 4 months ago

Io.
If
If 4(4x)^7 = 4^6^2
, then what is the value of x?​

Answers

Answered by architsavaliya175
2

Answer:

x=4^4=256

Step-by-step explanation:

4(4x)^7=4^6^2

4(4^7x^7)=4^36

4^7+1 x^7=4^36

4^8x^7=4^36

x^7=4^(36-8)

x^7=4^28

x=4^28/7

x=4^4

x=256

Answered by mandabhaskar2005
1

Step-by-step explanation:

4(4x)^7 = 4^12

(4x)^7 = 4^12 ÷ 4^1

(4x)^7 = 4^(12-1)

(4x)^7 = 4^11

4^7 × x^7 = 4^11

x^7 = 4^11 ÷ 4^7

x^7 = 4^(11-7)

x^7 = 4^4

x^7 = 256

x = 7 root of 256

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