Question

iod and frequency
A pendulum oscillates 40 times in 4 seconds. Find its time period and​

Answer 1

Answer:

Time period:-

40/4= 10times/sec.

Answer 2

Answer:

0.1 seconds, 10 Hz

Step-by-step explanation:

Given, number of oscillations = 40 and time = 4s.

It means time taken for 40 oscillations = 4 seconds

Hence, time taken for 1 oscillation = 4/40 = 0.1 seconds.

Thus, Time period = 0.1 second.

Now,

Frequency = Number of oscillations/Time

                  = 40/4

                  = 10 Hz.

Therefore,

Time period = 0.1 seconds

Frequency = 10 Hz

Hope it helps!