Iodine molecule dissociates into atoms after absorbing light of 4500Å .If one quantum of radiation is absorbed by each molecule , calculate the kinetic energy of iodine atoms . ( bond energy of iodine = 240 KJ/mole
Answers
Answer:
Energy given to I
2
molecule =
λ
hc
=
4500×10
−10
6.626×10
−34
×3.0×10
8
=4.417×10
−19
J
Also, energy used for breaking up of I
2
molecule is
N
A
B.E
=
6.023×10
23
240×10
3
=3.984×10
−19
J
∴ Energy used in imparting kinetic energy to two I atoms =(4.417−3.984)×10
−19
J
∴ KE/iodine atom
2
(4.417−3.984)
×10
−19
=0.216×10
−19
J
Explanation:
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Energy given to I 2 molecule = λ/hc
= 4500×10 −10 6.626×10 −34×3.0×10 8
=4.417×10 −19J
Also, energy used for breaking up of I 2 molecule is N A
B.E
= 6.023×10 23 240×10 3
=3.984×10 −19J
∴ Energy used in imparting kinetic energy to two I atoms =(4.417−3.984)×10
−19J
∴ KE/iodine atom
2(4.417−3.984)×10 −19
=0.216×10 ^-19 J