Iog26/33-log65/69+log55/46=0
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Step-by-step explanation:
log26/33-log65/69+log55/46=0
we know that,
loga-logb=loga/b
log26/33-log65/69=log26/33 ×69/65
=log46/55
log46/55+log55/46=0
we know that,
loga+logb=logab
log46/55×55/46
log1=0
hence proved
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