Math, asked by Austinnialayatt4204, 10 months ago

Iog26/33-log65/69+log55/46=0

Answers

Answered by lingam7983gmailcom
2

Answer:

0

Step-by-step explanation:

log26/33-log65/69+log55/46=0

we know that,

loga-logb=loga/b

log26/33-log65/69=log26/33 ×69/65

=log46/55

log46/55+log55/46=0

we know that,

loga+logb=logab

log46/55×55/46

log1=0

hence proved

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