Question

ion
13
NUMERICALS ON ACCELERATION
car starts from rest and picks up a velocity of 18 m/s in 10 seconds. Calculate the acceleratio
car.
Initial velocity (u) = 0 m/s (as the car starts from rest]
Final velocity (v) = 18 m/s
Time (t) = 10 sec
U-14
Acceleration =
f
18 m/s - 0 m/s 18 m/s
10 sec
10 s
1.8 m/s​

Answer 1

Given:-

• Initial velocity of car ,u = 0m/s

• Final velocity ,v = 18m/s

• time taken ,t = 10 s

To Find:-

• Acceleration of the car ,a

Solution:-

As we know that acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

where,

v is the final velocity

a is the acceleration

u is the initial velocity

t is the time taken

Substitute the value we get

→ a = 18-0/10

→ a = 18/10

→ a = 1.8 m/s²

Therefore, the acceleration of the car is 1.8 m/s².

Additional Information !!

Some equation of motion are

• v = u +at

• s = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

Answer:

$\huge \bf \: {Given}$

$\sf \blue {initial \: velocity \: (u) = 0 \: m \: per \: sec}$

$\sf \red {final \: velocity \: = 18 \: m \: per \: sec}$

$\sf \purple {time \: = 10 \: second}$

$\huge \bf \: To \: do$

$\sf \green {Acceleration \: of \: car}$

$\huge \bf \: Formula$

$\huge \boxed { \bf \: \frac{v - u}{t} }$

$\huge \bf \: Solution$

$\mathtt {here}$

$\texttt \blue {v \: = final \: velocity}$

$\texttt \green {u \: = initial \: velocity}$

$\texttt \red {t \: = time \: taken}$

$\texttt \purple {a = acceleration}$

$\tt \red \: acceleration \: = \dfrac{18 - 0}{10}$

$\tt \blue {acceleration \: = \dfrac{18}{10} }$

$\huge \fbox \orange {a \: = 1.8 \: m \: per \: sec}$