ion does not contain dπ pπ bonding in NO3
Answers
Answered by
0
Explanation:
In P=O bond, π - bond is formed by the sidewise overlapping of d - orbital of P and p - orbital of oxygen. Hence, it is formed by pπ and dπ overlapping.
In nitrogen and carbon, no vacant d-orbital is present. So, they do not form pπ−dπ
Answered by
0
Answer:
S in SO3 is sp2 hybridized. Three σ bonds are formed between the three sp2 hybridised orbital of sulphur and 3 pure p orbitals of three oxygen atoms.
We have one pure p orbital and two pure d orbitals in sulphur. These 3 orbitals are involved in one pπ−pπ bond and two pπ−dπ bonds.
Similar questions