Question

ionic strength (M) of 50 ml of 0.75 % (w/v) NaCl solution?

Answer 1

ANSWER 



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MOLARITY = MOL 
                     _____
                      L 

M = 0.75 M
V = 50 mL or 0.050 L
moles = P

 moles = P 

0.75M= P                                mol              =       0.050L

0.050L=P                       = mol

0.0375                           = P =    mol 

===============

0.0375 mol    NaCl    P        58.44g     

NaCl

1mol = NaCl

=2.19 grams          NaCl

Answer 2

So basically we have to find what is the ionic strength of 0.75g/100ml of Nacl solution

We know that 1M=58.44g/1L

or 58.44g/1L=1M

0.75g/100ml=1M*0.75g*1000ml/(58.5g*100ml)

                    =0.128 M