Question

Ionisation constant of ch3cooh is 1.7 * 10^ -5 and the conc. Of h+ ions is 3.4 * 10^ -4. Then find out the initial conc. Of ch3cooh molecules?

Answer 1

Answer: The initial concentration of $CH_3COOH$ is $6.8\times 10^{-3}M$

Explanation: The ionization reaction for $CH_3COOH$ follows:

            $CH_3COOH\rightarrow CH_3COO^-+H^+$

At $t=t_{eq}$         x              $3.4\times 10^{-4}$      $3.4\times 10^{-4}$

The ionization constant for the above reaction is written as:

$k=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}$

Putting values in above equation, we get:

$1.7\time 10^{-5}=\frac{(3.4\times 10^{-4})(3.4\times 10^{-4})}{x}\\\\x=6.8\times 10^{-5}$

Answer 2

Explanation:

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