Chemistry, asked by vishwasreddy948, 1 day ago

Ionisation energy and electron affinity of fluorine are 17.418 eV and 3.45 eV respectively, calculate the electronegativity of fluorine. XF = 0.187 (IE+EA) + 0.17 = 0.183 (17.418+3.45) + 0.17 = 4.07​

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Answered by ronaldocrviral
0

Answer:

10.434 answer in the image

Explanation:

10.434

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