Ionisation energy of He ion is 54.4 ev calculate
ionisation energy of Li ions?
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ionisation energy is the amount of energy required to remove an electron from an isolated gaseous atom.
from Bohr's theory,
ionisation energy, E = 13.6 × Z²/n² , where Z is atomic number and n is nth orbit from which an electron is ejected.
given, ionisation energy of He is 54.4 eV
for He , Z = 2 and n = 1
then, you will get, E = 13.6 × 2²/1² = 54.4eV
now for Lithium , Z = 3 And n = 1
so, ionisation energy ,E = 13.6 × Z²/n²
= 13.6 × (3)²/1²
= 13.6 × 9
= 122.4eV
hence, answer should be 122.4eV
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