Question

Ionisation energy of mg to mg^+2 is 22.67 ev atom ^-1. If first ionisation energy is 738 kj.mol^-1, the second ionisation energy of magnasium is (kj.mol^-1)​

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Answer 1

Answer:

The energy required to convert one Mg atom to Mg

2+

ion is the sum of first and second ionization potentials = 7.646+15.035=22.681eV

=96.5×22.681=2188.7kJ/mol

The atomic mass of Mg is 24 g/mol.

12 mg of Mg corresponds to 0.5 mmoles.

The amount of energy required to convert 0.5 mmol of Mg atoms to Mg

2+

ions = 0.5×10

−3

×2188.7=1.1kJ

Explanation:

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Answer 2

The energy required to convert one Mg atom to Mg2+ ion is the sum of first and second ionization potentials =  7.646+15.035=22.681eV

                            =96.5×22.681=2188.7kJ/mol

The atomic mass of Mg is 24 g/mol.

12 mg of Mg corresponds to 0.5 mmoles.

The amount of energy required to convert 0.5 mmol of Mg atoms to Mg2+ ions = 0.5×10−3×2188.7=1.1kJ

Hence, option C is correct.

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