Question

ionisation of NaOH is decreased in the presence of (a)AcOH (b)MeOH (c) EtOH (d) none of these

Answer 1

Answer:

Please mark me as brainless

Explanation:

AcOH

Answer 2

OPTION (a) IS CORRECT.

(a) AcOH

Explanation:

• Acid and Bases undergo "Neutralization" reaction.
• Sodium hydroxide is a base, when it will react with an acid it will form a salt.
• The acetic acid is an acid given in the options, so it will undergo neutralization reaction with sodium hydroxide and will form sodium acetate.
• NaOH will ionize to $Na^{+}$ and $OH^{-}$. Acetic acid will ionize to $CH_{3} COO^{-}$ and $H^{+}$.
• The ionization of sodium hydroxide will be decreased in presence of acetic acid as, free ions will not be present.
• Therefore, option (a) is correct.

$NaOH+CH_{3} COOH--->CH_{3} COONa+H_{2} O$