Question

Ionisation potential of Na would numerically be same as
1) Electron affinity of Na +
2) electrnegativity of Na+
3) Electron affinity of Ne
4) ionisation potential of Mg

Answer 1

1 ) electron affinity of Na+
Because IE is energy to remove electron . Electron affinity is released by the addition of electron.

Answer 2

Answer: The correct answer is Option 1.

Explanation:

Ionization potential is defined as the amount of energy which is required to remove an electron from an isolated gaseous atom to form a positively charged ion.

$X(g)\rightarrow X^{n+}(g)+ne^-$

Electron affinity is defined as the amount of energy released when an isolated gaseous atom gains an electron to form a negatively charged ion.

$X(g)+ne^-\rightarrow X^{n-}(g)$

Electronegativity is defined as the tendency of an element to attract the shared pair of electron towards itself in a compound.

Numerical value of ionization potential of neutral sodium metal will be equal to the electron affinity of sodium ion.

Ionization energy equation for Sodium:

$Na\rightarrow Na^++e^-$

Electron affinity equation for sodium ion:

$Na^++e\rightarrow Na$

Hence, the correct answer is Option 1.