Question

Ionization constant of AOH and BOH base are
K, and K, . Their relation is pK, <pk,
Conjugate of following base, does not show
maximum pH :
(1) AOH
(2) BOH
(3) Both of them (4) NOT​

Answer 1

Answer:

option 2 is correct acc. to formula:-

$ph = - log(h)$

where h is the no. of furnished hydogen ion.

Also pH is inversely proportional to pOH.

Answer 2

Ionization constant of AOH and BOH base are

K, and K, . Their relation is pK, <pk,

Conjugate of following base, does not show

maximum pH :BOH

Explanation:

Dissociation constant of base Kb

Let us consider base BOH dissolved in water

BOH + water --> B⁺ + OH⁻

Then K ={ B⁺][OH⁻]/[BOH][H₂O]

K x H₂O = { B⁺][OH⁻]/[BOH]

Kb={ B⁺][OH⁻]/[BOH]

Here , Kb is dissociation constant for base .

Higher the value of Kb , more is the basic strength .

Now , Pkb = - log Kb

It is noted, that higher the value of Kb corresponds to lower the value of Pkb.

We also know that the weak base have strong conjugate acid which have lower pH.

So, in above asked question : BOH is a weak base with strong conjugate acid and low value of pH .