Question

ionization energy for hydrogen atom in ergs, joules & eV respectively is-​

Answer 1

Answer:

option A

Explanation:

Because we know that,in joules, ionisation energy of H atom is :-

$2.18 \times 10 { }^{ - 12}$

Answer 2

Answer: Here is your answer↓

OPTION (A) 21.8 × 10^-12 ergs , 218 × 10^-20 joules and 13.6 eV.

Explanation:  ΔE = E∞ - E1

                       ΔE = 0-(-13.6 × z²/n²)eV

In this case we have hydrogen atom therefore Z =1 and N =1

                          ΔE = 13.6 eV  

now                    1 eV = 1.6 × 10^-19 joules

therefore             ΔE = 13.6 × 1.6 ×10^19

                            ΔE = 218 × 10^-20 joules

now                        1 joule = 10^7 ergs

                                 ΔE=218 × 10^-20 ×10^7  ergs

                                  ΔE = 21.8 ×10^-12 ergs

HENCE THE FINAL ANSWER IS ------- OPTION (A)21.8 × 10^-12 ergs , 218 × 10^-20 joules and 13.6 eV.