Question

Ionization energy for hydrogen atom in ergs joules and ev respectively is

Answer 1

For a hydrogen atom, composed of an orbiting electron bound to a nucleus of one proton, an ionization energy of 2.18 × 10−18 joule (13.6 electron volts) is required to force the electron from its lowest energy level entirely out of the atom.

Answer 2

Answer: Here is your answer↓

21.8 × 10^-12 ergs , 218 × 10^-20 joules and 13.6 eV.

Explanation:  ΔE = E∞ - E1

                        ΔE = 0-(-13.6 × z²/n²)eV

In this case we have hydrogen atom therefore Z =1 and N =1

                           ΔE = 13.6 eV  

now                    1 eV = 1.6 × 10^-19 joules

therefore             ΔE = 13.6 × 1.6 ×10^19

                             ΔE = 218 × 10^-20 joules

now                        1 joule = 10^7 ergs

                                  ΔE=218 × 10^-20 ×10^7  ergs

                                   ΔE = 21.8 ×10^-12 ergs

HENCE THE FINAL ANSWER IS -------21.8 × 10^-12 ergs , 218 × 10^-20 joules and 13.6 eV.