Ionization energy of 1 mole of Na atom is 495kJ/mole.
How much energy is required for converting 4.6mg of Na in Na ion?
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23 g --> 495 kJ
No. of moles(n) = given weight/ Gram atomic weight
n = 4.6 x 10⁻³/23
Ereq = 4.6 x 10⁻³ x 495 x 10³/23 = 99J
So 99J of energy is required
Hope This Helps!
No. of moles(n) = given weight/ Gram atomic weight
n = 4.6 x 10⁻³/23
Ereq = 4.6 x 10⁻³ x 495 x 10³/23 = 99J
So 99J of energy is required
Hope This Helps!
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hope this helps ...
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