Ionization energy of hydrogen atom 13.6 electron volt the energy required to excited from ground state to the next higher state is
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0
Answer:
it's 10.2 eV
Explanation:
The energy required to excited an electron in hydrogen atom from the ground state to the next higher state, if the ionisation energy for the hydrogen atom is 13.6 eV is : 10.2 eV
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Answered by
1
Answer:
Ionization energy of hydrogen atom=−13.6Z
2
=−13.6eV
E
ionization
=
λ
hc
λ
ionisation
6.626×10
−34
×3×10
8
=13.6×1.6×10
−19
λ
ionisation
=912×10
−8
m
ionization energy for 1 mole H=E
ionization
×N
A
=13.6×1.6×10
−19
×6.023×10
23
=1310kJ/mole
=1313kJ/mol(approx)
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