Question

Ionization potential of hydrogen atom is 13.6 V. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. The spectral lines emitted by hydrogen atoms according to Bohr's theory will be(a) One(b) Two(c) Three(d) Four

Answer 1

Answer: c -->3

Explanation: 3.4 eV after round off it will be 3.

Answer 2

Answer:

(c) Three is the correct answer.

Explanation:

Given data:

Ionization potential

of hydrogen atom = 13.6 V

Hydrogen atoms in the ground state are excited by monochromatic radiation.

photon energy = 12.1 eV.

To find :

The spectral lines emitted by hydrogen atoms according to Bohr's =?

We know that

Ionization energy = -13.6 eV

Energy of electron in the excited state will be = ionization energy+ photon energy

= -13.6+12.1

= -1.5 eV.

Also, energy of electron in nth orbit is

E = -13.6/ n^2

n^2 = -13. 6/-1.5

n^2 = 9

n = 3

Since n = 3, the possible number of spectral lines will be transited from third to second, second to first and third to first.

Hence, the number of spectral lines are 3.

Hence,

(c) Three is the correct answer.

Note : ionization potential is the minimum required energy to remove and electron from its isolated gaseous state.