Math, asked by praneeta27, 7 months ago

iota , iota2 , iota 3​

Answers

Answered by Anonymous
11

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iota , iota2 , iota 3

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i =  \sqrt{ - }

 {i}^{2}  =  - 1

 {i}^{3}  =  {i}^{2}  \times i =   - 1 \times i =  - i

Here is your answer^^^^

Hope it helps you..!!!

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