Question

iota , iota2 , iota 3​

Answer 1

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iota , iota2 , iota 3

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$i = \sqrt{ - }$

${i}^{2} = - 1$

${i}^{3} = {i}^{2} \times i = - 1 \times i = - i$

Here is your answer^^^^

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