Question

IP= ₹5000, R= 5% and I=₹200 Then find time​

Answer 1

Answer:

rs . 500

Step-by-step explanation:

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Answer 2

Time - Simple Interest

Simple Interest is the method of calculating the interest amount for a particular principal amount of money at some rate of interest.

But in this question, we have been asked to calculate the time period, which can be calculate only with the formula of simple interest.

The basic formula of Simple Interest is as follows:

$\longrightarrow SI = \dfrac{P \times R \times T}{100}$

Where,

• P - Principal Amount
• R - Rate of Interest
• T - Time Period

According to the given question, we've been given that,

• Simple interest, SI = Rs. 200
• Principal amount, P = Rs. 5000
• Rate of interest, R = 5%
• Time period, T = ?

Solution:

By using the simple interest formula and substituting all the given values, we get the following results:

$\implies SI = \dfrac{P \times R \times T}{100} \\ \\ \implies 200 = \dfrac{50\cancel{00} \times 5 \times T}{1\cancel{00}} \\ \\ \implies 200 = 50 \times 5 \times T \\ \\ \implies 200 = 250 \times T \\ \\ \implies T = \cancel{\dfrac{200}{250}} \\ \\ \implies \boxed{\bf{T = 0.8}}$

Hence, the time period is 0.8 years.

$\rule{300}{2}$

Important formulae

Simple interest SI on a certain sum of money of Rs P invested at the rate of R% per annum for T years is given by,

$\implies \boxed{\rm{SI = \dfrac{P \times R \times T}{100}}}$

Simple interest SI on a certain sum of money of Rs P invested at the rate of R% per month for n months is given by,

$\implies \boxed{\rm{SI = \dfrac{P \times R \times n}{12 \times 100}}}$

Simple interest SI on a certain sum of money of Rs P invested at the rate of R% per day (non-leap year) for d days is given by,

$\implies \boxed{\rm{SI = \dfrac{P \times R \times d}{365 \times 100}}}$