Question

ip tp and tq are tangent drawm from con external point t with the circle centre o if tp=4cm,op=3cm,find ot​

Answer 1

Answer:

As op is perpendicular to tp.

So triangle opt is right angke triangle.

Using pythagoras theorem

${ot}^{2} = {op}^{2} + {tp}^{2} \\ = {3}^{2} + {4}^{2} \\ = 9 + 16 \\ = 25 \\ = {5}^{2} \\ = > ot = 5 \: cm$

Answer 2

Answer:

$5cm$

is the answer........