Question

IP3:
Solve: (x2D2 + xD + 1)y = In x.sin(In x), x > 0​

Answer 1

Answer:

Under the transformation x = et (when x > 0) for ... The general solution is y(x) = 1 x2. (Acos(3 lnx) + B sin(3 lnx)). (iii) Using the ... x2D2 + xD = D2, =⇒ x2D2 = D2 − D = D(D − 1).