Question

ipti class 10
The sum of first 2 points
16 terms of the
AP: 10, 6, 2... is​

Answer 1

Answer:

Sn = n/2 × (2a + (n-1)d )

Here , n= 16, d= 6 - 10 = -4, a = 10

So , S16 = 16/2 × (2×10 + (16-1) ×-4 )

= 8 × (20 + (15 × -4 ) )

= 8 × ( 20 + (-60) )

= 8 × (-40)

= -320

The sum of first 16 terms of the AP is -320.

Step-by-step explanation:

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Answer 2

Answer:

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