Question

Iqbal treated a lustrous, divalent element M with sodium hydroxide.

He observed the formation of bubbles in reaction mixture. He made

the same observations when this element was treated with

hydrochloric acid. Suggest how he can identify the produced gas. Write chemical equations for both the reaction​

Answer 1

Answer:

Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. ... Hence, hydrogen gas is most likely to be produced during these reactions.

Explanation:

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Answer 2

In the first case; a base reacts with a metal, and in the second case; an acid reacts with a metal. Hence, hydrogen gas is most likely to be produced during these reactions.

The evolution of hydrogen gas can be checked by bringing a burning matchstick or splinter near the evolved gas. The fact that the matchstick burns with a pop sound, shows that hydrogen gas is evolved.

The reactions can be shown by following equations:

2NaOH + Zn ⇨ Na2ZnO2 + H2

2HCl + Zn ⇨ ZnCl2 + H2

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