Science, asked by Pr8u2gdalSurastar, 1 year ago

Iqbal treated a lustrous, divalent element M with sodium hydroxide. he observed the formation of bubbles in reaction mixture. he made the same observations when this element was treated with hydrochloric acid. suggest how can he identify the produced gas. write chemical equations for both the reactions.

Answers

Answered by prmkulk1978
172

Its A Divalent Element And Lustrous So Its A Metal

Second Thing Only Very Reactive Metals React With Sodium Hydroxide.

Very Reactive Metals React With Sodium Hydroxide To Give Hydrogen Gas.

Now He Can Identify It By Bringing A Burning Candle He Would See That Gas Burns With A Pop Sound.

There Are Possible Metals Are

Calcium And Magnesium And Zinc And Many More

These Are Possible.

Now Reaction Could Be

Ca+NaOH-----------> Salt+ Hydrogen

Mg+NaOH------------> Salt + Hydrogen

Zn+NaOH----------> Salt + Hydrogen

All Of Them Give Complex Salts.

When They React With HCl They Give Their Respective Chlorides With H2 Gas


Answered by b2003
92

The element is a metal

M+ 2 NaOH---------Na2MO2+ H2

M+2Hcl-----Mcl2+h2

The produced gas can be identify by bringing a matchstick near the reaction vessels the gas burns with pop sound this conform that the gas is H2

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