Ir 2A camrent flows through bulb in 3 minute. The amount of charge flown will be
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since the current is charge flowing per second so,
we ,say, I=q/t
,here, I=2 A
t=3 minute= 3×60=180 second
now , we need to find q=?
so,
2=q/180
q=360 coulomb
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