Question

ir a and i are two mut vectors such that a 126 and 5m 46 are perendicular to each other, then ihe 19le bely & and his​

Answer 1

$\large\boxed{\textsf{\textbf{\blue{S0LUTI0N\::-}}}}$

Given :-

A student gets 60 marks out of 80 in his first test and 70 marks out of 80 in his second test.

To Find :-

What is the percentage increase in the second test.

Solution :-

$\mapsto$ In case of marks get out of 80 in his first test :

$\implies$ 60 marks

$\mapsto$ In case of marks get out of 80 in his second test :

$\implies$ 70 marks

Now, we have to find the total score percentage in the first and second test :

${\small{\bold{\purple{\underline{\bigstar\: In\: case\: of\: first\: test\: :-}}}}}$

As we know that :

$\longmapsto \sf\boxed{\bold{\pink{Total\: percentage\: scored =\: \dfrac{Total\: marks\: obtained}{Total\: marks} \times 100}}}$

Given :

Total marks obtained = 60 marks

Total marks = 80 marks

According to the question by using the formula we get,

$\leadsto \sf Total\: Percentage\: scored\: in\: {1}^{{st}}\: test\: =\: \dfrac{60}{8\cancel{0}} \times 10{\cancel{0}}$

$\leadsto \sf Total\: Percentage\: scored\: in\: {1}^{{st}}\: test =\: \dfrac{60}{8} \times 10$

$\leadsto \sf Total\: Percentage\: scored\: in\: {1}^{{st}}\: test =\: \dfrac{60 \times 10}{8}$

$\leadsto \sf Total\: Percentage\: scored\: in\: {1}^{{st}}\: test =\: \dfrac{\cancel{600}}{\cancel{8}}$

$\leadsto \sf\bold{\green{Total\: Percentage\: scored\: in\: {1}^{{st}}\: test =\: 75\%}}$

Hence, the student scored 75% in the first test.

Answer 2

Total Percentage scored in 1 st test=75%

Hence, the student scored 75% in the first test...