Ir ∆SBH, LS = 76°, LB = 48°: angle h =
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what is LS and LB .this question is incomplete please write whole question
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in the give figure ,
LS =76° and LB = 48°
LET ANGLE ANGLE H BE X.
THEN THE SUM OF TRIANGLE IS 180°,
LS+LB+LH=180°
76°+48°+ X=180°
124+X=180°
X=180°-124= 56°
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