Question

Ir tan A+ cot A = 10/3, evaluate tan^2A+ cot^2A.​

Answer 1

Squaring on both sides ,

$\tt {tan}^{2} A + {cot}^{2} A = \frac{100}{9}$

Answer 2

Answer:

$\: Squaring \: on \: both \: sides , \\ </p><p>\tt {tan}^{2} A + {cot}^{2} A = \frac{100}{9}</p><p>\begin{gathered} \\ \\ \end{gathered}$

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