Ir the pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 1°C its
mitial temperature must be
(1) 250K (b) 250°C (0) 25°C (d) 25K
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Answer:
Let P2 = 1.004 P1 ..... A 0.4% increase in P
Let T2 = T1 + 1 ........... See note below
P1V1/T1 = P2V2/T2 ..... combined gas law
P1/T1 = P2/T2 ............... Assume V remains constant.
T1 = P1T2 / P2 .............. solve for T1
T1 = P1(T1+1) / (1.004P1)
T1 = (T1+1) / 1.004
1.004T1 = T1 + 1
1.004T1 - T1 = 1
0.004T1 = 1
T1 = 1 / 0.004
T1 = 250K
Note: A 1 degree increase on the Celsius scale is a 1 degree increase on the Kelvin scale. Temperatures used in the combined gas law must be in Kelvin.
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