Question

Irfan deposits 10000in a bank for a certain time and gets 600 as interest . If he deposis 8000 at the same rate of interest for the same time period then find the interest he will get at the end. ​

Answer 1

Answer:

Interest at the end for 8000 rs principle amount = 750 rs

Step-by-step explanation:

\begin{gathered}\textbf{Formula of Interest = }\frac{P* R* T}{100}\textbf{Firstly for principle P1 = 10,000 rs, Interest was I1 = 600 rs}\\\\\\\textbf{Then principle P2 = 8,000 rs ,and Interest is I2 }\\\textbf{Rate and Time are same in both case.So }\\\\\text{Dividing I2/I1 =}\frac{(P1RT)/100} {(P2RT)/100} \\\\\\\\\\\textbf{I2/600 =P1/P2}\\ \\\\\text{Multiplying both sides by I1 = 600}\\\textbf{ So Interest I2 = (10,000/8000)*600}\\\\\textbf{So Interest = (10*600)/8 = 750 rs}\end{gathered}

Formula of Interest =

100

P∗R∗T

Firstly for principle P1 = 10,000 rs, Interest was I1 = 600 rs

Then principle P2 = 8,000 rs ,and Interest is I2

Rate and Time are same in both case.So

Dividing I2/I1 =

(P2RT)/100

(P1RT)/100

I2/600 =P1/P2

Multiplying both sides by I1 = 600

So Interest I2 = (10,000/8000)*600

So Interest = (10*600)/8 = 750 rs