Question

Iron exhibits bcc structure of room temperature at above 900 it transfer to fcc structure the ratio of density iron of room temperature to that at 900 cassuming molar mass and atomic radii of iron remains constant with temperature

Answer 1

Answer:

In fcc atoms along face diagram touch each other i.e,`sqrt(2)a = 4r`<br> In fcc atoms along body diagram touch each other i.e,`sqrt(3)a = 4r`<br> BCC FCC <br> `4r = sqrt(3) a 4r = sqrt(2) a` <br> `4r = sqrt(3)a 4r = sqrt(2)a` <br> `a = (4r)/(sqrt(3)) a= (4r)/(sqrt(2))` <br> `(d_(BC C))/(d_(FC C))= ((Z_(BC C) xx M)/(N_(A)a^(3)))/((Z_(FC C) xx M)/(N_(Aa^(3)))) = ((Na((4r)/(sqrt(3)))^(3))/(4xxM))/(N_(A) xx((4r)/(sqrt(3)))^(3)) = (3)/(4) sqrt((3)/(2))`

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