Iron fillings and sulphur powder were mixed together and divided into two
parts A and S. Part A was heated strongly while part C was not heated.
Dilute HCl was added to both the parts and evolution of gas was seen in both the cases. How will you identify the gases evolved? Give the equations for the reactions taking place.
Answers
Answer:
the answer is in the explanation :)
Explanation:
As part 'A' is heated, a compound FeS is formed by the reaction between iron filings and sulphur. When dilute HCl is added to part A, FeS will react with dil HCl to form H2S gas which has smell of rotten eggs and will turn lead acetate paper black.
Fe(s)+S(s)−→−HeatFeS(s)
FeS(s)+2HCl(dil.)→FeCl2(aq)+H2S(g)
(CH3COO)2Pb(aq)Lead acetate+H2S(g)→PbS(s)Black ppt+2CH3COOHAcetic acid
As part 'S' in not heated, so S is a mixture of iron fillings and sulphur powder. When dil, HCl is added to it, iron filings react with dill. HCl to form H2(g) which burns with a 'pop' sound if burning match stick is brought near it.
Fe(s)+2HCl(dil.)→FeCl2(aq)+H2(g)
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Answer:
When dilute HCl is added to part A, FeS will react with dil HCl to form H2S gas which has smell of rotten eggs and will turn lead acetate paper black. As part 'B' in not heated, so B is a mixture of iron fillings and sulphur powder. When dil, HCl is added to it, iron filings react with dill.
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