Chemistry, asked by ruchitavaidya28, 9 months ago

Iron fillings and sulphur were mixed together and divided into two parts A and B part I was heated strongly while part B was not heated dillute sulphuric acid was added to the both the parts and evolution of gas was seen in both the cases how will you identify the gases evolved

Answers

Answered by shubhamkumar099
0

Answer:

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Answered by Palash221206
0

Answer:

As part 'A' is heated, a compound FeS is formed by the reaction between iron filings and sulphur. When dilute HCl is added to part A, FeS will react with dil HCl to form H2S gas which has smell of rotten eggs and will turn lead acetate paper black.

Fe(s)+S(s)−→−HeatFeS(s)

FeS(s)+2HCl(dil.)→FeCl2(aq)+H2S(g)

(CH3COO)2Pb(aq)Lead acetate+H2S(g)→PbS(s)Black ppt+2CH3COOHAcetic acid  

As part 'B' in not heated, so B is a mixture of iron fillings and sulphur powder. When dil, HCl is added to it, iron filings react with dill. HCl to form H2(g) which burns with a 'pop' sound if burning match stick is brought near it.

Fe(s)+2HCl(dil.)→FeCl2(aq)+H2(g)

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