Iron(II) sulfate, is typically the source of iron in tablets prescribed to anemic patients, a condition where a person lacks enough healthy red blood cells. The tablets can be dissolved in dilute sulfuric acid to dissolve the Fe2+ ions. To determine the percentage by mass of iron within the tablets, the Fe2+ ions can be oxidised to Fe3+ using potassium permanganate, where MnO4− is reduced to Mn2+. Calculate the percentage by mass of iron in a 500 mg tablet that requires 24.53 cm3 of 0.0100 mol dm−3 KMnO4 to titrate the iron sample. State your answer to 3 significant figures. M(Fe) = 55.85 g mol−1
Answers
Answered by
0
not able to understand what your question is
Answered by
1
Hey friend plzz ask the question...not a paragraph
Similar questions