Question

iron occurs as BBC structure. If effective radius of iron atom is 124pm, calculate the density of iron ​

Answer 1

we know for bcc
$r = \frac{a}{2 \sqrt{2} } \\ 124 \times {10}^{ - 10} = a$
we know

$row \: p = \frac{z \times m}{n \times {a}^{3} } \\ row \: p = \frac{2 \times 26}{ {6.022 \times 10}^{23} \times {124 \times 10}^{ - 10} } \\ row \: p = {0.0696 \ \times 10}^{ - 22}$
density= 0•0693cm^3/s