Question

Iron oxide crystal panes effects on arsenic adsorption

Answer 1

Qp = Pco2/Pco

= 0.8/1.4 = 0.571

you can see that , Kp < Qp , the reaction will go in reverse direction . due to this pressure of CO2 will decreases and that of CO will increase to attain equilibrium .

Hence, Pco2 = (0.8 - P) and Pco = (1.4 + p)

Kp = Pco2/Pco

0.265 = (0.8 - p)/(1.4 + p)

0.265(1.4 + p) = 0.8 - p

0.265p + 0.265 × 1.4 = 0.8 - p

1.265p = 0.8 - 0.371 = 0.429

p = 0.429/1.265 = 0.339 atm

Hence, at equilibrium ,

pressure of CO2 ( Pco2) = 0.8 - 0.339 = 0.461 atm.

pressure of CO ( Pco ) = 1.4 + 0.339 = 1.739 atm