Question

iron oxide have formula Fe0.94O. What fraction of Fe occurs as Fe3+?​

Answer 1

Answer:Fe2+)x (Fe3+)yO.

On looking at the given formula of the compound

x + y = 0.93 ... (1)

Total positive charge on ferrous and ferric ions should balance the two units of negative charge on oxygen. Therefore,

2x + 3y = 2 ... (2)

⇒ x + 3/2y = 1... (3)

On subtracting equation (1) from equation (3) we have

3/2y − y = 1 − 0. 93

⇒ 1/2y = 0.07

⇒ y = 0.14

On putting the value of y in equation (1) we get,

x + 0.14 = 0.93

⇒ x = 0.93 – 0.14

x = 0.79

Fraction of Fe2+ ions present in the sample = 0.79/0.93 = 0.81

Metal deficiency defect is present in the sample because iron is less in amount than that required for stoichiometric composition.

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