Math, asked by vandanabindlish255, 10 months ago

Irrational numbers between 4 and 6

Answers

Answered by ahsaanhassan6
9

Answer:

sqrt 17=4.123105626.....

Step-by-step explanation:

Answered by syed2020ashaels
3

The given question is that we have to find the irrational numbers between 4 and 6.

6 can be written as √16 and 6 can be written as √36.

Therefore any root value between 16 and 36 will be expected number and it should not include the number 25 because the number 25 is a perfect square number.

let's take the numbers between 16 and 36.

√18, √21, √22, √23, √32, √35 and so on.

The value of √18 is 4.2426

The value of √21 is 4.58

The value of √22 is 4.69

The value of √32 is 5. 565.

Therefore, the required irrational numbers are

 \sqrt{18 }\\  \sqrt{21 }\\  \sqrt{22} \\  \sqrt{32}\\  \sqrt{33}

# spj2

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